Another mother gives birth to 8 babies (octuplets) in US.

The six boys and two girls were delivered by caesarean section in Los Angeles, California.

The babies, who weighed in at between 1.8lbs (820g) and 3.4lbs each, are all said to be doing well.

They were screaming and kicking around very vigorously, according to a doctor at the hospital in suburban Bellflower.

The mother, whose identity has not been revealed, has asked that limited information be released about the births.

A hospital spokeswoman described the deliveries, which took place in the space of five minutes, as “truly amazing”.

Three of the babies – who were nine weeks premature – need help breathing, but all were otherwise doing well, she said.

Doctors say the babies will be in incubators for at least six weeks and that the mother is planning to breast feed them all.

Giving birth to several babies is just normal, I think. But what made me wonder is the fact that 3 of the 8 babies were nine weeks premature. Does it mean that these 3 babies were formed when their mother was nine weeks pregnant of the other 5?

If that’s what really happened, then it means that there is an abnormality in the hormones of that woman (just my thought). What I understand is that, normally if a woman is already pregnant, there would be something (may be a hormone) in the uterus that would prevent the spermcells in going inside the uterus from the vagina, or in another way, something would prevent the release of the eggcells, which in turns prevent more fertilization.

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